document.write( "Question 1125872: Assume that 32.9% of people have sleepwalked. Assume that in a random sample of 1521 adults, 542 have sleepwalked.
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document.write( "a. Assuming that the rate of 32.9% is correct, find the probability that 542 or more of the 1521 adults have sleepwalked.
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document.write( "b. Is that result of 542 or more significantly high?
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document.write( "c. What does the result suggest about the rate of 32.9%? \n" );
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Algebra.Com's Answer #742214 by Boreal(15235) You can put this solution on YOUR website! a. 549/1521=36.1% \n" ); document.write( "z=(p-phat)/sqrt(p*(1-p)/n) \n" ); document.write( "=0.032/sqrt(0.329*0.671/1521) \n" ); document.write( "=2.66 \n" ); document.write( "b. probability z>2.66 is 0.0039 \n" ); document.write( "This is about 2/5 ths of one percent, considered to be statistically significant. \r \n" ); document.write( "\n" ); document.write( "c. That suggests that perhaps the quoted rate of 32.9% is too low. \n" ); document.write( " |