document.write( "Question 1125874: A women bought a number of items for $48. She realizes that if she bought 6 more items for the same money, she would have paid $4 less per item. How many items did she buy? \n" ); document.write( "
Algebra.Com's Answer #742196 by greenestamps(13200)\"\" \"About 
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\n" ); document.write( "This is a good example of a problem where a formal algebraic solution is far more work than an informal solution using logical analysis.

\n" ); document.write( "Algebraically, we have

\n" ); document.write( "x = number of items
\n" ); document.write( "y = price per item
\n" ); document.write( "(1) \"xy+=+48\"
\n" ); document.write( "(2) \"%28x%2B6%29%28y-4%29\" = 48

\n" ); document.write( "Solve (1) for y and substitute in (2):

\n" ); document.write( "\"y+=+48%2Fx\"
\n" ); document.write( "\"%28x%2B6%29%28%2848%2Fx%29-4%29+=+48\"
\n" ); document.write( "\"48-4x%2B288%2Fx-24+=+48\"
\n" ); document.write( "\"-4x-24%2B288%2Fx+=+0\"
\n" ); document.write( "\"x%2B6-72%2Fx+=+0\"
\n" ); document.write( "\"x%5E2%2B6x-72+=+0\"
\n" ); document.write( "\"%28x%2B12%29%28x-6%29+=+0\"
\n" ); document.write( "\"x+=+-12\" (nonsense) or \"x+=+6\"

\n" ); document.write( "The woman bought 6 items for $8 each, for a total of $48. She could have bought 6+6 = 12 items for $8-$4 = $4 each and spent the same total of $48.

\n" ); document.write( "Whew!! That was rather ugly....

\n" ); document.write( "How can you solve the problem far more easily with logical reasoning? Simply find two pairs of numbers whose product is 48 that fit the conditions of the problem.

\n" ); document.write( "48 = 1*48
\n" ); document.write( "48 = 2*24
\n" ); document.write( "48 = 3*16
\n" ); document.write( "48 = 4*12
\n" ); document.write( "48 = 6*8

\n" ); document.write( "Those last two satisfy the conditions of the problem....
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