document.write( "Question 1125874: A women bought a number of items for $48. She realizes that if she bought 6 more items for the same money, she would have paid $4 less per item. How many items did she buy? \n" ); document.write( "
Algebra.Com's Answer #742196 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "This is a good example of a problem where a formal algebraic solution is far more work than an informal solution using logical analysis. \n" ); document.write( "Algebraically, we have \n" ); document.write( "x = number of items \n" ); document.write( "y = price per item \n" ); document.write( "(1) \n" ); document.write( "(2) \n" ); document.write( "Solve (1) for y and substitute in (2): \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The woman bought 6 items for $8 each, for a total of $48. She could have bought 6+6 = 12 items for $8-$4 = $4 each and spent the same total of $48. \n" ); document.write( "Whew!! That was rather ugly.... \n" ); document.write( "How can you solve the problem far more easily with logical reasoning? Simply find two pairs of numbers whose product is 48 that fit the conditions of the problem. \n" ); document.write( "48 = 1*48 \n" ); document.write( "48 = 2*24 \n" ); document.write( "48 = 3*16 \n" ); document.write( "48 = 4*12 \n" ); document.write( "48 = 6*8 \n" ); document.write( "Those last two satisfy the conditions of the problem.... \n" ); document.write( " \n" ); document.write( " |