document.write( "Question 1125804: Deandre bought a desktop computer and a laptop computer. Before finance charges, the laptop cost
\n" ); document.write( "$300 more than the desktop. He paid for the computers using two different financing plans. For the desktop the interest rate was 9% per year, and for the laptop it was 7% per year. The total finance charges for one year were $365. How much did each computer cost before finance charges?
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Algebra.Com's Answer #742157 by kasperk(4)\"\" \"About 
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Let $D = cost of the desktop
\n" ); document.write( "Then $D + $300 = cost of the laptop
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\n" ); document.write( "DESKtop computer:
\n" ); document.write( "Principal amount = D
\n" ); document.write( "r = 9% = .09
\n" ); document.write( "t = 1 year
\n" ); document.write( "Therefore, using a simple interest formula I = Prt, we find I = D·(0.09)·1 = 0.09D
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\n" ); document.write( "LAPtop computer:
\n" ); document.write( "Principal amount = D+300
\n" ); document.write( "r = 7% = .07
\n" ); document.write( "t = 1 year
\n" ); document.write( "Therefore, I = Prt = (D+300)·(0.07)·1 = 0.07(D+300) = 0.07D + 21\r
\n" ); document.write( "\n" ); document.write( "If we add up the interest on the desktop and the interest on the laptop, that total interest should equal $365 (interestingly, $1 per day of the year!):
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\n" ); document.write( "0.09D + 0.07D + 21 = 365
\n" ); document.write( "Combine like terms:
\n" ); document.write( "0.16D + 21 = 365
\n" ); document.write( "Subtract 21 from each side of the equation:
\n" ); document.write( "0.16D = 344
\n" ); document.write( "Divide both sides of the equation by 0.16:
\n" ); document.write( "D = $2150 = desktop computer cost
\n" ); document.write( "D + 300 = $2450 = laptop computer cost
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