document.write( "Question 1125826: If logb 2 =0.4 and logb 3=0.7,then what is logb 12=?\r
\n" ); document.write( "\n" ); document.write( "a 3√xy
\n" ); document.write( "b 1/3xy
\n" ); document.write( "c 1/3(x+y)
\n" ); document.write( "d 1/3 x+y
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Algebra.Com's Answer #742141 by josgarithmetic(39620)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "If logb 2 =0.4 and logb 3=0.7,then what is logb 12=?
\n" ); document.write( "--\r
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\n" ); document.write( "\n" ); document.write( "\"log%28%2812%29%29\"
\n" ); document.write( "\"log%28%282%2A2%2A3%29%29\"
\n" ); document.write( "\"log%28%282%5E2%29%29%2Blog%28%283%29%29\"
\n" ); document.write( "\"2%2Alog%28%282%29%29%2Blog%28%283%29%29\"
\n" ); document.write( "but your choices look very strange.\r
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\n" ); document.write( "\n" ); document.write( "Substituting according to your givens,\r
\n" ); document.write( "\n" ); document.write( "\"2%2A0.4%2B0.3\", easily computed.
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