document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=102137>Question 102137</A>: <I><SPAN STYLE=\"word-break: break-all;\"> FIND FOUR CONSECUTIVE INTEGERS SUCH THAT THE SUM OF THE SECOND AND FOURTH IS 132 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #74214 by </B><A HREF=/tutors/aboutme.mpl?userid=Kalmetam><B>Kalmetam(43)</B></A><img src=\"/images/stars/stars-07.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Kalmetam><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=74214\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Well, half of it must be one of the numbers.. The 2nd and fourth MUST be the ones 1 before and 1 after the half number because 1 over plus 1 under equals the whole number, in this case, 132..  So that must mean that the 3rd number is half! Half is 66.  So that is the 3rd number so the rest is obvious..\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "64,65,66,67\r<BR>\n" );
document.write( "\n" );
document.write( "65+67=132\r<BR>\n" );
document.write( "\n" );
document.write( "Now we know the answer </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );