document.write( "Question 1125684: Choose one of the proofs below and use one of the indirect proof techniques (reductio ad absurdum or conditional proof) presented in Chapter 8 to demonstrate the validity of the argument. The proofs below may use any of the rules of inference or replacement rules given in Chapter 8.\r
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document.write( "(G • P) → K, E → Z, ~P → ~ Z, G → (E v L), therefore, (G • ~L) → K
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document.write( "(S v T) ↔ ~E, S → (F • ~G), A → W, T → ~W, therefore, (~E • A) → ~G
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document.write( "(S v T) v (U v W), therefore, (U v T) v (S v W)
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document.write( "~Q → (L → F), Q → ~A, F → B, L, therefore, ~A v B
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document.write( "~S → (F → L), F → (L → P), therefore, ~S → (F → P)
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Algebra.Com's Answer #742019 by jim_thompson5910(35256)![]() ![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "I'm going to pick on the first line \n" ); document.write( "(G • P) → K, E → Z, ~P → ~ Z, G → (E v L), therefore, (G • ~L) → K \n" ); document.write( "to prove that out. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "I'll do so in two ways. The first of which is through a conditional proof\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "Start with the antecedent of the conclusion, which is (G & ~L) and show how it leads to K \n" ); document.write( " ![]() \n" ); document.write( "\n" ); document.write( "note: I used an ampersand in place of a dot\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "------------------------------------------------------------------------------ \n" ); document.write( "Then I'll show how to do a proof by contradiction (aka reductio ad absurdum), which is an indirect proof. \r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "The idea is to assume the complete opposite the conclusion, and then show how a contradiction arises. \n" ); document.write( " ![]() \n" ); document.write( " \n" ); document.write( " |