document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1125561>Question 1125561</A>: <I><SPAN STYLE=\"word-break: break-all;\"> the personnel office at a large electronics firm regularly schedules job interviews and maintains records of the interviews.  from the past records, they have found that the length of a first interview is normally distributed, with a mean = 34 minutes and a standard deviation = 7 minutes.  (round your answers to four decimal places.) \r<BR>\n" );
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document.write( "a-what is the probability that a first interview will last 40 minutes or longer?<BR>\n" );
document.write( "b-two first interviews are usually scheduled per day.  what is the probability that the average length of the two interviews will be 40 minutes or longer? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #742011 by </B><A HREF=/tutors/aboutme.mpl?userid=Boreal><B>Boreal(15235)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Boreal><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Boreal><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=742011\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> a. z=(x-mean)/sd<BR>\n" );
document.write( "z>(6/7), so probability is 0.1957\r<BR>\n" );
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document.write( "second is z=(xbar-mean)/sigma/sqrt(n)<BR>\n" );
document.write( "z>6/7/sqrt(2) or 6 sqrt(2)/7 and that probability is less, or 0.1131 </SPAN>\n" );
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