document.write( "Question 1125686: A printer has ink that is 4% cobalt blue color and ink that is 26% cobalt blue color. How many ounces of each ink are needed to make 3 gallons (384 ounces) of ink that is 15% cobalt blue color? \n" ); document.write( "
Algebra.Com's Answer #741991 by FrankM(1040)\"\" \"About 
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Let 4% solution be L (gal) (For 'light' color)
\n" ); document.write( "Let 26% solution be D (gal) (For 'dark' color)\r
\n" ); document.write( "\n" ); document.write( ".04 L + .26 D = .45 (because 15% of 3 gal is .45 gal of 'color'.\r
\n" ); document.write( "\n" ); document.write( "and \r
\n" ); document.write( "\n" ); document.write( "L + D = 3\r
\n" ); document.write( "\n" ); document.write( "Multiply 1st eq by 100\r
\n" ); document.write( "\n" ); document.write( "4 L +26 D = 45\r
\n" ); document.write( "\n" ); document.write( "Mult 2nd eq by 4\r
\n" ); document.write( "\n" ); document.write( "4L + 4D = 12\r
\n" ); document.write( "\n" ); document.write( "subtract, and 22D = 33 D=1.5 and L = 1.5\r
\n" ); document.write( "\n" ); document.write( "Note, that since 15 = (4+26) /2 , I knew that the mix would be equal parts of each. The solution provides the full steps for any mixure problem worded this way.
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