document.write( "Question 1125603: Find the inverse of the function from the ‘procedural perspective’ discussed in Example 6.1.5
\n" ); document.write( "
\n" ); document.write( "\"matrix%281%2C3%2C%0D%0A%22f%28x%29%22%2C+%22%22=%22%22%2Clog%282%2C%2810x-20%29%29%29\"
\n" ); document.write( "
\n" ); document.write( "

Algebra.Com's Answer #741918 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "\"+f%28x%29=log%282+%2C%2810x-20%29%29+\"\r
\n" ); document.write( "\n" ); document.write( "change the base, replace \"f%28x%29+\"with \"y\":\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"+y=log%28%2810x-20%29%29%2F+log%28%282%29%29\"\r
\n" ); document.write( "\n" ); document.write( "Interchange the variables:\r
\n" ); document.write( "\n" ); document.write( "\"+x=log%28%2810y-20%29%29%2F+log%28%282%29%29\"\r
\n" ); document.write( "\n" ); document.write( "solve or \"y\"\r
\n" ); document.write( "\n" ); document.write( "\"+x%2Alog%28%282%29%29=log%28%2810y-20%29%29\"\r
\n" ); document.write( "\n" ); document.write( "\"+log%28%282%5Ex%29%29=log%28%2810y-20%29%29\" ...since log equals, we will have\r
\n" ); document.write( "\n" ); document.write( "\"+2%5Ex=10y-20\" \r
\n" ); document.write( "\n" ); document.write( ".\"+2%5Ex%2B20=10y\" \r
\n" ); document.write( "\n" ); document.write( "\"+y=%282%5Ex%2B20%29%2F10\" \r
\n" ); document.write( "\n" ); document.write( "\"+y=%281%2F10%29%282%5Ex%2B20%29\"->your inverse \r
\n" ); document.write( "\n" ); document.write( "so, replace \"y\" with \"+f%5E-1%28x%29\":\r
\n" ); document.write( "\n" ); document.write( "\"+f%5E-1%28x%29=%281%2F10+%29%282%5Ex+%2B+20%29\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );