document.write( "Question 1125603: Find the inverse of the function from the ‘procedural perspective’ discussed in Example 6.1.5
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Algebra.Com's Answer #741905 by Edwin McCravy(20055)\"\" \"About 
You can put this solution on YOUR website!
\"matrix%281%2C3%2C%0D%0A%22f%28x%29%22%2C+%22%22=%22%22%2Clog%282%2C%2810x-20%29%29%29\"
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document.write( "That has the red graph, with the blue vertical asymptote:\r\n" );
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document.write( "Replace f(x) by y\r\n" );
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document.write( "\"matrix%281%2C3%2C%0D%0A%22y%22%2C+%22%22=%22%22%2Clog%282%2C%2810x-20%29%29%29\"\r\n" );
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document.write( "Interchange x and y\r\n" );
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document.write( "\"matrix%281%2C3%2C%0D%0A%22x%22%2C+%22%22=%22%22%2Clog%282%2C%2810y-20%29%29%29\"\r\n" );
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document.write( "Solve for y.\r\n" );
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document.write( "Raise 2 to the both sides power:\r\n" );
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document.write( "\"matrix%281%2C3%2C%0D%0A2%5Ex%2C+%22%22=%22%22%2C2%5E%28log%282%2C%2810y-20%29%29%29%29\"\r\n" );
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document.write( "Use a rule of logs \"a%5E%28+log%28a%2C%28b%29%29%29+=b\" on the right side:\r\n" );
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document.write( "\"matrix%281%2C3%2C%0D%0A2%5Ex%2C+%22%22=%22%22%2C10y-20%29\"\r\n" );
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document.write( "\"matrix%281%2C3%2C%0D%0A-10y%2C%22%22=%22%22%2C-2%5Ex-20%29\"\r\n" );
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document.write( "Divide both sides by -10\r\n" );
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document.write( "\"matrix%281%2C3%2C%0D%0Ay%2C%22%22=%22%22%2C2%5Ex%2F10%2B2%29\"\r\n" );
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document.write( "Replace y by f-1(x)\r\n" );
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document.write( "f-1 =\"2%5Ex%2F10%5E%22%22%2B2\"   <--- the answer!\r\n" );
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document.write( "This has the green graph with the blue horizontal asymptote:\r\n" );
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document.write( "Put the original red function together with its green inverse on the \r\n" );
document.write( "same set of axes:\r\n" );
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document.write( "Now if we draw the identity line (dotted) whose equation is y = x,\r\n" );
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document.write( "we see that the green inverse function is the red original function\r\n" );
document.write( "reflected across the dotted identity line which has equation y = x.\r\n" );
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document.write( "Edwin
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