document.write( "Question 1125606: Analytically show that the function f(x)=10-∛(x-8)
\n" ); document.write( "is one-to-one, find its inverse, and evaluate the following:\r
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\n" ); document.write( "\n" ); document.write( " f^(-1) (11)\r
\n" ); document.write( "\n" ); document.write( " f^(-1) (12)\r
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Algebra.Com's Answer #741902 by jim_thompson5910(35256)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "If f(x) is one-to-one, then \"f%28a%29=f%28b%29\" implies that \"a+=+b\" for all a,b in the domain of f(x). Put in plain english: if two output values are the same, then the inputs must be the same for the function to be one-to-one.\r
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\n" ); document.write( "\n" ); document.write( "Consider a counter-example such as a parabola. We can have the same output lead to two different inputs (eg: y = 4 lead to x = -2 and x = 2 for the function y = x^2). This is a reason why a parabola is not one-to-one.\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29+=+10-root%283%2Cx-8%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%28a%29+=+10-root%283%2Ca-8%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"f%28b%29+=+10-root%283%2Cb-8%29\"\r
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\n" ); document.write( "\n" ); document.write( "If \"f%28a%29+=+f%28b%29\", then...\r
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\n" ); document.write( "\n" ); document.write( "\"f%28a%29+=+f%28b%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"10-root%283%2Ca-8%29+=+10-root%283%2Cb-8%29\" Substitution\r
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\n" ); document.write( "\n" ); document.write( "\"-root%283%2Ca-8%29+=+-root%283%2Cb-8%29\" Subtract 10 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"root%283%2Ca-8%29+=+root%283%2Cb-8%29\" Multiply both sides by -1\r
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\n" ); document.write( "\n" ); document.write( "\"a-8+=+b-8\" Cube both sides\r
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\n" ); document.write( "\n" ); document.write( "\"a+=+b\" Add 8 to each side\r
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\n" ); document.write( "\n" ); document.write( "So we end up with \"a+=+b\" after assuming \"f%28a%29+=+f%28b%29\"\r
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\n" ); document.write( "\n" ); document.write( "So this means that \"f%28a%29+=+f%28b%29\" leads to \"a+=+b\". If we follow the steps shown above in reverse, then we'll go from \"a+=+b\" to \"f%28a%29+=+f%28b%29\"\r
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\n" ); document.write( "\n" ); document.write( "Therefore, we have proven that f(x) is indeed one-to-one.\r
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\n" ); document.write( "\n" ); document.write( "Let's find the inverse. Which I'll call g(x)\r
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\n" ); document.write( "\n" ); document.write( "g(x) = f^(-1)(x)\r
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\n" ); document.write( "\n" ); document.write( "\"f%28x%29+=+10-root%283%2Cx-8%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"y+=+10-root%283%2Cx-8%29\" Replace f(x) with y\r
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\n" ); document.write( "\n" ); document.write( "\"x+=+10-root%283%2Cy-8%29\" Swap x and y. From here on out, we're solving for y.\r
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\n" ); document.write( "\n" ); document.write( "\"x-10+=+-root%283%2Cy-8%29\" Subtract 10 from both sides\r
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\n" ); document.write( "\n" ); document.write( "\"-root%283%2Cy-8%29+=+x-10\" \r
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\n" ); document.write( "\n" ); document.write( "\"root%283%2Cy-8%29+=+-x%2B10\" Multiply both sides by -1\r
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\n" ); document.write( "\n" ); document.write( "\"y-8+=+%28-x%2B10%29%5E3\" Cube both sides\r
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\n" ); document.write( "\n" ); document.write( "\"y+=+%28-x%2B10%29%5E3%2B8\" Add 8 to both sides\r
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\n" ); document.write( "\n" ); document.write( "The inverse is \"g%28x%29+=+%28-x%2B10%29%5E3%2B8\"\r
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\n" ); document.write( "\n" ); document.write( "Let's use the inverse to compute the inputs x = 10, x = 11, x = 12\r
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\n" ); document.write( "\n" ); document.write( "\"g%28x%29+=+%28-x%2B10%29%5E3%2B8\"\r
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\n" ); document.write( "\n" ); document.write( "\"g%2810%29+=+%28-10%2B10%29%5E3%2B8\"\r
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\n" ); document.write( "\n" ); document.write( "\"g%2810%29+=+%280%29%5E3%2B8\"\r
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\n" ); document.write( "\n" ); document.write( "\"g%2810%29+=+0%2B8\"\r
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\n" ); document.write( "\n" ); document.write( "\"g%2810%29+=+8\"\r
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\n" ); document.write( "\n" ); document.write( "------\r
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\n" ); document.write( "\n" ); document.write( "\"g%28x%29+=+%28-x%2B10%29%5E3%2B8\"\r
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\n" ); document.write( "\n" ); document.write( "\"g%2811%29+=+%28-11%2B10%29%5E3%2B8\"\r
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\n" ); document.write( "\n" ); document.write( "\"g%2811%29+=+%28-1%29%5E3%2B8\"\r
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\n" ); document.write( "\n" ); document.write( "\"g%2811%29+=+-1%2B8\"\r
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\n" ); document.write( "\n" ); document.write( "\"g%2811%29+=+7\"\r
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\n" ); document.write( "\n" ); document.write( "\"g%28x%29+=+%28x%2B10%29%5E3%2B8\"\r
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\n" ); document.write( "\n" ); document.write( "\"g%2812%29+=+%28-12%2B10%29%5E3%2B8\"\r
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\n" ); document.write( "\n" ); document.write( "\"g%2812%29+=+%28-2%29%5E3%2B8\"\r
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\n" ); document.write( "\n" ); document.write( "\"g%2812%29+=+-8%2B8\"\r
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\n" ); document.write( "\n" ); document.write( "\"g%2812%29+=+0\"
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