document.write( "Question 1125600: The area of a rectangle is 45, and its perimeter is 28. Find its dimensions and diagonal. \n" ); document.write( "
Algebra.Com's Answer #741898 by MathLover1(20849)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "let dimensions be \"L\" and \"W\"\r
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\n" ); document.write( "\n" ); document.write( "given:\r
\n" ); document.write( "\n" ); document.write( "The area of a rectangle is \"45\", so we have \r
\n" ); document.write( "\n" ); document.write( "\"L%2AW=45\"....solve or \"W\"\r
\n" ); document.write( "\n" ); document.write( "\"W=45%2FL\"......eq.1\r
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\n" ); document.write( "\n" ); document.write( "its perimeter is \"28\", so we have\r
\n" ); document.write( "\n" ); document.write( " \"2%28L%2BW%29=28\"\r
\n" ); document.write( "\n" ); document.write( "\"L%2BW=14\" ...solve or \"W\"\r
\n" ); document.write( "\n" ); document.write( "\"W=14-L\"...eq.2\r
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\n" ); document.write( "\n" ); document.write( "from eq.1 and eq.2 we have\r
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\n" ); document.write( "\n" ); document.write( "\"45%2FL=14-L\"...solve or \"L\"\r
\n" ); document.write( "\n" ); document.write( "\"45=14L-L%2AL\"\r
\n" ); document.write( "\n" ); document.write( "\"45=14L-L%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"L%5E2-14L%2B45=0\"\r
\n" ); document.write( "\n" ); document.write( "\"%28L+-+9%29+%28L+-+5%29+=+0\"\r
\n" ); document.write( "\n" ); document.write( "solutions:\r
\n" ); document.write( "\n" ); document.write( "\"%28L+-+9%29++=+0\"-> \"L=9\"
\n" ); document.write( "or
\n" ); document.write( "\"%28L+-+5%29++=+0\"-> \"L=5\"\r
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\n" ); document.write( "\n" ); document.write( "go to eq.2, substitute \"L=9\"\r
\n" ); document.write( "\n" ); document.write( "\"W=14-L\"...eq.2\r
\n" ); document.write( "\n" ); document.write( "\"W=14-9\"\r
\n" ); document.write( "\n" ); document.write( "\"W=5\"\r
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\n" ); document.write( "\n" ); document.write( "so, we will choose the length to be \"highlight%28L=9%29\" and the width to be \"highlight%28W=5%29\"-> dimensions\r
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\n" ); document.write( "\n" ); document.write( "and we can ind diagonal \"d\" using Pythagorean theorem since diagonal cuts rectangle into two right angle triangles where diagonal is actually hypotenuse\r
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\n" ); document.write( "\n" ); document.write( "\"d%5E2=L%5E2%2BW%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"d%5E2=9%5E2%2B5%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"d%5E2=81%2B25\"\r
\n" ); document.write( "\n" ); document.write( "\"d%5E2=106\"\r
\n" ); document.write( "\n" ); document.write( "\"d=sqrt%28106%29\"\r
\n" ); document.write( "\n" ); document.write( "\"d=10.295630140987\"\r
\n" ); document.write( "\n" ); document.write( "approximately\r
\n" ); document.write( "\n" ); document.write( "\"highlight%28d=10.3%29\"\r
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