document.write( "Question 1125597: The width of a rectangle is 9 less than twice its length. If the area of the rectangle is 101 cm2, what is the length of the diagonal? \n" ); document.write( "
Algebra.Com's Answer #741897 by MathLover1(20850)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "let the length be \"L\", and the width \"W\"\r
\n" ); document.write( "\n" ); document.write( "if the width of a rectangle is \"9\" less than \"twice\" its length,we have\r
\n" ); document.write( "\n" ); document.write( "\"W=2L-9\"....eq.1\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "if the area of the rectangle is \"A=101cm%5E2\", we have\r
\n" ); document.write( "\n" ); document.write( "\"L%2AW=101cm%5E2\"....eq.2\r
\n" ); document.write( "\n" ); document.write( "substitute \"W\" from eq.1\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"L%282L-9%29=101cm%5E2\"...solve for \"L\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"2L%5E2-9L=101cm%5E2\"\r
\n" ); document.write( "\n" ); document.write( "\"2L%5E2-9L-101cm%5E2=0\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "use quadratic formula\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"L+=+%28-%28-9%29+%2B-+sqrt%28+%28-9%29%5E2-4%2A2%2A%28-101%29+%29%29%2F%282%2A2%29+\"\r
\n" ); document.write( "\n" ); document.write( "\"L+=+%289+%2B-+sqrt%2881%2B808+%29%29%2F4+\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "\"L+=+%289+%2B-+sqrt%28889+%29%29%2F4+\"\r
\n" ); document.write( "\n" ); document.write( "since length, we need only positive solution\r
\n" ); document.write( "\n" ); document.write( "\"L+=+%289+%2B+sqrt%28889+%29%29%2F4+\"\r
\n" ); document.write( "\n" ); document.write( "\"L+=+%289+%2B+29.8161%29%2F4+\"\r
\n" ); document.write( "\n" ); document.write( "\"L+=+38.8161%2F4+\"\r
\n" ); document.write( "\n" ); document.write( "\"L+=+9.704025+\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "now find \"W\"\r
\n" ); document.write( "\n" ); document.write( "\"W=2%2A9.704025-9\"....eq.1\r
\n" ); document.write( "\n" ); document.write( "\"W=19.40805-9\"\r
\n" ); document.write( "\n" ); document.write( "\"W=10.40805\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "check the area:\r
\n" ); document.write( "\n" ); document.write( "\"L%2AW=101cm%5E2\"
\n" ); document.write( "\"10.40805%2A9.704025=101cm%5E2\"
\n" ); document.write( "\"100.99997740125=101cm%5E2\"...round it
\n" ); document.write( "\"101=101cm%5E2\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "
\n" ); document.write( "
\n" );