document.write( "Question 1125542: Mrs. Inere can sell 50 brownie boxes each month if she charges $95 for each box. She estimates that for every $5 increase in price, she will sell 2 boxes less. Find the price that would yield the maximum revenue. \n" ); document.write( "
Algebra.Com's Answer #741862 by Theo(13342)\"\" \"About 
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she sells 50 brownie boxes when they are 95 dollars each.\r
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\n" ); document.write( "\n" ); document.write( "her total revenue is 50 * 95 = 4750\r
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\n" ); document.write( "\n" ); document.write( "she estimates that she will sell 2 boxes less for every 5 dollar incfrease in the price of 1 box.\r
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\n" ); document.write( "\n" ); document.write( "the equation for that is y = (50 - 2x) * (95 + 5x).\r
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\n" ); document.write( "\n" ); document.write( "each time x goes up 1 unit, the number of boxes goes down 2 and the price of each box goes up 5.\r
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\n" ); document.write( "\n" ); document.write( "multiply the factors together to get y = 50 * 95 + 50 * 5x - 2x * 95 - 2x * 5x.\r
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\n" ); document.write( "\n" ); document.write( "simplify to get y = 4750 + 250x - 190x - 10x^2\r
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\n" ); document.write( "\n" ); document.write( "combine like terms to get y = 4750 + 60x - 10x^2\r
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\n" ); document.write( "\n" ); document.write( "rearrange the terms in descending order of degree to get:\r
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\n" ); document.write( "\n" ); document.write( "y - -10x^2 + 60x + 4750\r
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\n" ); document.write( "\n" ); document.write( "this is a quadratic equation in standard form where:\r
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\n" ); document.write( "\n" ); document.write( "a = -10
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\n" ); document.write( "\n" ); document.write( "the maximum value of this equation will occur when x = -b/(2a)\r
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\n" ); document.write( "\n" ); document.write( "x = -b/(2a) becomes x = -60 / -20 = 3.\r
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\n" ); document.write( "\n" ); document.write( "when x = 3, y = -10 * 3^2 + 60 * 3 + 4750 = 4840.\r
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\n" ); document.write( "\n" ); document.write( "when x = 3, she sells 50 - 6 = 44 boxes at 95 + 15 = 110 dollars each for total revenue of 44 * 110 = 4840.\r
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\n" ); document.write( "\n" ); document.write( "for her, it doesn't get any better than that.\r
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\n" ); document.write( "\n" ); document.write( "here's the graph of the equation that shows when the maximum revenue occurs.\r
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\n" ); document.write( "\n" ); document.write( "the blue line is the graph of the equations.\r
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\n" ); document.write( "\n" ); document.write( "since the equations are equivalent, they draw the same line on the graph.\r
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\n" ); document.write( "\n" ); document.write( "the orange line is there to show the value of the curve when x = 3.\r
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