document.write( "Question 1125527: Amy is driving her car to a conference . The expression d = 65t + 100 represents her total distance from home in miles, and t is the number of hours since 8:00 AM.\r
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Algebra.Com's Answer #741859 by Theo(13342)\"\" \"About 
You can put this solution on YOUR website!
the equation is 65 * t + 100\r
\n" ); document.write( "\n" ); document.write( "t is the number of hours since 8:00 am.
\n" ); document.write( "d is her distance from home.\r
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\n" ); document.write( "\n" ); document.write( "at 12:00 noon, she has been on the road for 4 hours (12 - 8 = 4).\r
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\n" ); document.write( "\n" ); document.write( "d = 65 * t + 100 becomes d = 65 * 4 + 100 which becomes d = 260 + 100 which results in d = 360 miles from home.\r
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\n" ); document.write( "\n" ); document.write( "the d-intercept would be the value of d when t = 0.\r
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\n" ); document.write( "\n" ); document.write( "when t = 0, the equation becomes d = 65 * 0 + 100 which results in d = 100.\r
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\n" ); document.write( "\n" ); document.write( "in context of this problem, i believe this means she was already 100 miles from home when she started at 8:00 am.\r
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\n" ); document.write( "\n" ); document.write( "this might be easier to see if you let y = d and you let x = t.\r
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\n" ); document.write( "\n" ); document.write( "the equation then becomes y = 65 * x + 100.\r
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\n" ); document.write( "\n" ); document.write( "the d-intercept now becomes the y-intercept, which is the value of y when x = 0.\r
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\n" ); document.write( "\n" ); document.write( "you can graph the equation of d = 65t + 100 by replacing d with y and t with x.\r
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\n" ); document.write( "\n" ); document.write( "the graph looks like this.\r
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\n" ); document.write( "\n" ); document.write( "the blue line is the graph of the equation.\r
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\n" ); document.write( "\n" ); document.write( "the orange lines are there to show the intersection points of the equation when x = 0 and x = 4.\r
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