document.write( "Question 1125493: In triangle ABC, B is 15 less than two times A. If C is 3 degrees larger than B, find the three angles.
\n" ); document.write( "a+b+c=180
\n" ); document.write( "b=a.a-15
\n" ); document.write( "c=b+3
\n" ); document.write( "b= (a2-15)+3
\n" ); document.write( "b= ( \n" ); document.write( "
Algebra.Com's Answer #741828 by MathTherapy(10552)\"\" \"About 
You can put this solution on YOUR website!
In triangle ABC, B is 15 less than two times A. If C is 3 degrees larger than B, find the three angles.
\n" ); document.write( "a+b+c=180
\n" ); document.write( "b=a.a-15
\n" ); document.write( "c=b+3
\n" ); document.write( "b= (a2-15)+3
\n" ); document.write( "b= (
\n" ); document.write( "
Let angle A be A
\n" );
document.write( "Then angle B = 2A - 15
\n" );
document.write( "And, angle C = 2A - 15 + 3, or 2A - 12
\n" );
document.write( "As the 3 angles sum to 180o, we get: A + 2A - 15 + 2A - 12 = 180
\n" );
document.write( "5A = 207
\n" );
document.write( "Solve that for A, angle A's measurement.
\n" );
document.write( "Subtract 15 from TWICE A to get B's measurement.
\n" );
document.write( "Subtract 12 from TWICE A to get C's measurement.
\n" );
document.write( "That's it!! It's as SIMPLE as that!! \n" );
document.write( "
\n" );