document.write( "Question 1125451: A mason can lay the bricks in a sidewalk in 10 hours. The mason's apprentice requires 12 hours to do the same job. After working together for 3 hours, the mason leaves for another job and the apprentice continues working. How long will it take the apprentice to complete the job? (Round your answer to two decimal places.)
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Algebra.Com's Answer #741776 by rothauserc(4718)\"\" \"About 
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the hourly rate for the mason is 1/10
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\n" ); document.write( "the mason's apprentice's hourly rate is 1/12
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\n" ); document.write( "together 1/10 + 1/12 = 11/60 per hour is their combined rate
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\n" ); document.write( "taking the reciprocal, 60/11 hours to complete the job together
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\n" ); document.write( "together they worked at a rate of 11/60 for three hours
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\n" ); document.write( "11/60 * 3 = 11/20 of the job was done in 3 hours
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\n" ); document.write( "this leaves 1 - 11/20 = 9/20 of the job for the apprentice
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\n" ); document.write( "divide by the apprentice's rate (9/20)/(1/12) = 9/20 * 12/1 = 9/5 * 3 = 27/5
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\n" ); document.write( "it takes the apprentice 5.40 hours to complete the job
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