document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=102037>Question 102037</A>: <I><SPAN STYLE=\"word-break: break-all;\">   find the line perpendicular to y=(-11/12)x+25/6 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #74176 by </B><A HREF=/tutors/aboutme.mpl?userid=Fombitz><B>Fombitz(32388)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Fombitz><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Fombitz><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=74176\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  <BR>\n" );
document.write( "Find the slope of the perpendicular line.\r<BR>\n" );
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document.write( "For two lines to be perpendicular, their slopes are negative reciprocals of each other.  \r<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m%5B2%5D+=+-1%2Fm%5B1%5D ALIGN=MIDDLE  ALT=\"m%5B2%5D+=+-1%2Fm%5B1%5D\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "Or in your case <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m%5B2%5D+=+-%281%2F%28-11%2F12%29%29 ALIGN=MIDDLE  ALT=\"m%5B2%5D+=+-%281%2F%28-11%2F12%29%29\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=m%5B2%5D+=+12%2F11 ALIGN=MIDDLE  ALT=\"m%5B2%5D+=+12%2F11\"   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( "Since you didn't specify any points for the perpindicular line to pass through, you can choose the origin (0,0) as a point on the line. The slope-intercept form of the line equation is <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=m%5B2%5D%2Ax%2Bb%5B2%5D ALIGN=MIDDLE  ALT=\"y=m%5B2%5D%2Ax%2Bb%5B2%5D\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=0=%2812%2F11%29%2A0%2Bb%5B2%5D ALIGN=MIDDLE  ALT=\"0=%2812%2F11%29%2A0%2Bb%5B2%5D\"   DISABLED_style= \"max-width:90%; height:auto;\" > Slope is 12/11 from above and (0,0) is a point on the line. <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%5B2%5D=0 ALIGN=MIDDLE  ALT=\"b%5B2%5D=0\"   DISABLED_style= \"max-width:90%; height:auto;\" > Solve for <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=b%5B2%5D ALIGN=MIDDLE  ALT=\"b%5B2%5D\"   DISABLED_style= \"max-width:90%; height:auto;\" >. <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=y=%2812%2F11%29%2Ax ALIGN=MIDDLE  ALT=\"y=%2812%2F11%29%2Ax\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "Graphically : <BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=+graph%28+300%2C+300%2C+-5%2C+5%2C++-5%2C++5%2C+%28-11%2F12%29%2Ax%2B25%2F6%2C%2812%2F11%29%2Ax%29 ALIGN=MIDDLE   DISABLED_style= \"max-width:90%; height:auto;\" > <BR>\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );