document.write( "Question 1125291: The following data is associated with the problem:\r
\n" ); document.write( "\n" ); document.write( "Year Population (in millions)
\n" ); document.write( "1950 6.79
\n" ); document.write( "1960 27.81
\n" ); document.write( "1970 45.59
\n" ); document.write( "1980 69.01
\n" ); document.write( "1990 84.39
\n" ); document.write( "2000 110.21\r
\n" ); document.write( "\n" ); document.write( "A: use x=0 for 1950, x=10 for 1960,....
\n" ); document.write( "The linear regression equation that best fits this data in the form y=ax+b is: ______________. Round the constants to the nearest thousandth.\r
\n" ); document.write( "\n" ); document.write( "B: Use your regression equation to predict the population if x=5.15\r
\n" ); document.write( "\n" ); document.write( "c: Approximate in what year the population reaches 38.05 million.
\n" ); document.write( "

Algebra.Com's Answer #741721 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Year Population (in millions)\r
\n" ); document.write( "\n" ); document.write( "\"x\"|\"y\"
\n" ); document.write( "\"1950\"|\"+6.79\"
\n" ); document.write( "\"1960\"|\"+27.81\"
\n" ); document.write( "\"1970\"|\"+45.59\"
\n" ); document.write( "\"1980\"|\"+69.01\"
\n" ); document.write( "\"1990\"|\"+84.39\"
\n" ); document.write( "\"2000\"|\"+110.21\"\r
\n" ); document.write( "\n" ); document.write( "A:
\n" ); document.write( "use \"x=0+\" for \"1950\", \"x=10\" for \"1960\",....
\n" ); document.write( "\"x\"|\"y\"
\n" ); document.write( "\"0\"|\"+6.79\"
\n" ); document.write( "\"10\"|\"+27.81\"
\n" ); document.write( "\"20\"|\"+45.59\"
\n" ); document.write( "\"30\"|\"+69.01\"
\n" ); document.write( "\"40\"|\"+84.39\"
\n" ); document.write( "\"50\"|\"+110.21\"\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "The linear regression equation that best fits this data in the form \"y=ax%2Bb\" is: \r
\n" ); document.write( "\n" ); document.write( "\"y=ax%2Bb\" use \"x=0\"|\"+y=6.79\"\r
\n" ); document.write( "\n" ); document.write( "\"6.79=a%2A0%2Bb\"
\n" ); document.write( "\"b=6.79\"\r
\n" ); document.write( "\n" ); document.write( "\"y=ax%2Bb\" use \"x=10\"|\"+y=27.81\" and \"b=6.79\"\r
\n" ); document.write( "\n" ); document.write( "\"27.81=10a%2B6.79\"
\n" ); document.write( "\"27.81-6.79=10a\"
\n" ); document.write( "\"21.02=10a\"
\n" ); document.write( "\"a=21.02%2F10\"
\n" ); document.write( "\"a=2.102\"
\n" ); document.write( "
\n" ); document.write( "_____ \"y=2.102x%2B6.79\" _________. Round the constants to the nearest thousandth.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "B: Use your regression equation to predict the population if \"x=5.15\"\r
\n" ); document.write( "\n" ); document.write( "\"y=2.102%2A5.15%2B6.79\"
\n" ); document.write( "\"y=10.8253%2B6.79\"
\n" ); document.write( "\"y=17.615\"
\n" ); document.write( "c: Approximate in what year the population reaches \"38.05\" million. \r
\n" ); document.write( "\n" ); document.write( "\"38.05=2.102x%2B6.79\"
\n" ); document.write( "\"38.05+-6.79++=2.102x\"
\n" ); document.write( "\"31.26++=2.102x\"
\n" ); document.write( "\"31.26+%2F2.102=x\"
\n" ); document.write( "\"x=14.9\"....Approximately\r
\n" ); document.write( "\n" ); document.write( "since \"x=10\" represents year \"1960\", \"x=14.9=10%2B4.9\" will represent \"1960%2B4.9=1964.9\" year which means in year \"1964\", and almost \"11\" months which means in November, \"1964\"\r
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