document.write( "Question 1125393: Given that: p²+q²=11pq, where p and q are constants, show that ½(logp+logq) equals:
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Algebra.Com's Answer #741713 by ikleyn(52781)\"\" \"About 
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\n" ); document.write( "\n" ); document.write( "            Notice that the condition  ASSUMES  that  p > 0;  q > 0,\r
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\n" ); document.write( "\n" ); document.write( "(a)   show that  \"%281%2F2%29%2A%28log%28p%29%2Blog%28q%29%29\"  equals  log \"%28%28p%2Bq%29%2Fsqrt%2813%29%29%29\"\r
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document.write( "\"p%5E2+%2B+q%5E2\" = 11pq  ====>  add 2pq to both sides. You will get  ====>\r\n" );
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document.write( "\"p%5E2+%2B+2pq+%2B+q%5E2\" = 13pq  ====>\r\n" );
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document.write( "\"%28p%2Bq%29%5E2\" = 13pq  ====>  take the logarithm from both sides ====>\r\n" );
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document.write( "2*log(p+q) = log(13) + log(p) + log(q)\r\n" );
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document.write( "2*log(p+q) - log(13) = log(p) + log(q)\r\n" );
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document.write( "2*(log(p+q) - 2*log(sqrt(13))) = log(p) + log(q)\r\n" );
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document.write( "log \"%28%28p%2Bq%29%2F%28sqrt%2813%29%29%29\" = \"%281%2F2%29%2A%28log%28p%29+%2B+log%28q%29%29\".\r\n" );
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