document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=102032>Question 102032</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find three consecutive integers such that twice the least integer is 12 more than the greatest integer.\r<BR>\n" );
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document.write( "2x = x + 12<BR>\n" );
document.write( " x = 12\r<BR>\n" );
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document.write( "Dont know what to do from here.\r<BR>\n" );
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document.write( "Thanks, K.R. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #74171 by </B><A HREF=/tutors/aboutme.mpl?userid=bucky><B>bucky(2189)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=bucky><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=74171\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let's start by defining the three consecutive integers.<BR>\n" );
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document.write( "If x represents the least of the three, then the next consecutive integer is x+1 and the <BR>\n" );
document.write( "next consecutive integer is 1 more than that ... or x + 2<BR>\n" );
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document.write( "So the three consecutive integers are x, x+1, and x+2.<BR>\n" );
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document.write( "Twice the least integer is, as you correctly wrote, 2x.<BR>\n" );
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document.write( "12 more than the greatest integer is x+2 + 12 = x + 14<BR>\n" );
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document.write( "Since these two amounts must be equal, you can write:<BR>\n" );
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document.write( "2x = x + 14<BR>\n" );
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document.write( "Now you need to get rid of the x on the right side so that you end up with all the terms<BR>\n" );
document.write( "containing x on one side of the equation and everything else on the other side. You can<BR>\n" );
document.write( "get rid of the x on the right side by subtracting x from the right side. But if you subtract<BR>\n" );
document.write( "something from the right side, you must also subtract it from the left side to keep the<BR>\n" );
document.write( "equation in balance. So subtract x from both sides. When you do that, the x disappears<BR>\n" );
document.write( "from the right side and the left side becomes 2x minus x which is just x.<BR>\n" );
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document.write( "So the equation is reduced to:<BR>\n" );
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document.write( "x = 14<BR>\n" );
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document.write( "If x is 14 then the next two consecutive integers are 15 and 16 ... x+1 and x+2. So the<BR>\n" );
document.write( "three consecutive integers are 14, 15, and 16.<BR>\n" );
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document.write( "Check ... the least integer is 14. Twice the least integer is 28. Is 28 actually 12 more<BR>\n" );
document.write( "than the greatest integer which is 16? Yes it is, so the problem checks.<BR>\n" );
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document.write( "You were on the right track, but you just needed to know the difference in the three integers<BR>\n" );
document.write( "was that they were x, x+1, and x+2. Hope this helps to show you how you could work the<BR>\n" );
document.write( "problem through to get the final answer.<BR>\n" );
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