document.write( "Question 1125382: https://vle.mathswatch.co.uk/images/questions/question2408.png
\n" );
document.write( "please help me, thanks :) \n" );
document.write( "
Algebra.Com's Answer #741699 by Theo(13342)![]() ![]() You can put this solution on YOUR website! if they're similar, then their sides are proportional.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that gets you x / 4x = (x + 2) / 48\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "cross multiply to get 48x = 4x * (x + 2)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "simplify to get 48x = 4x^2 + 8x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "subtract 48x from both sides to get 0 = 4x^2 + 8x - 48x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "combine like terms to get 0 = 4x^2 - 40x\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "factor to get 0 = 4x * (x - 10)\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "solve for x to get x = 0 or x = 10\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "x = 0 is not good, so it has to be x = 10 or not at all.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "when x = 10, the smaller figure is 10 by 12 and the larger figure is 40 by 48.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "the sides are proportional, as they should be with similar figures.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "10 / 40 = 12 / 48\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "cross multiply to get 480 = 480, confirming the ratios are equal which confirms that the sides are proportional.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "your solution is that the width of the badge is 40 cm.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "that's the larger pentagon that has the smaller pentagon as part of it, if i understand the problem correctly.\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |