document.write( "Question 1125382: https://vle.mathswatch.co.uk/images/questions/question2408.png
\n" ); document.write( "please help me, thanks :)
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Algebra.Com's Answer #741697 by MathLover1(20849)\"\" \"About 
You can put this solution on YOUR website!
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\n" ); document.write( "\n" ); document.write( "if pentagons are similar, corresponding sides are proportional; so, we have\r
\n" ); document.write( "\n" ); document.write( "\"4x%3A48=x%3A%28x%2B2%29\".............solve for \"x\"\r
\n" ); document.write( "\n" ); document.write( "\"4x%28x%2B2%29=48x\" ...simplify
\n" ); document.write( "\"cross%284%29cross%28x%29%28x%2B2%29=cross%2848%2912cross%28x%29\"
\n" ); document.write( "\"%28x%2B2%29=12\"
\n" ); document.write( "\"x=12-2\"
\n" ); document.write( "\"x=10\"\r
\n" ); document.write( "\n" ); document.write( "dimensions of greater pentagon are:
\n" ); document.write( "\"4x%2Acm=4%2A10cm=40cm\" and \"48cm\"\r
\n" ); document.write( "\n" ); document.write( "dimensions of smaller pentagon are:
\n" ); document.write( "\"x=10\" and \"x%2B2=12\"\r
\n" ); document.write( "\n" ); document.write( "I hope you can find out what the width of the badge is.\r
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