document.write( "Question 1125383: https://vle.mathswatch.co.uk/images/questions/question2399.png. please I need help with this hard problem :) thanks \n" ); document.write( "

Algebra.Com's Answer #741695 by MathLover1(20849) $\"\"$ $\"About$

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\n" ); document.write( "here you have $\"two\"$ right angle triangles, $\"CEA\"$ and $\"CDB\"$ \r
\n" ); document.write( "\n" ); document.write( "the area o the trapezium $\"ABDE\"$ is equal to the difference of the area of $\"CEA\"$ and $\"CDB\"$ \r
\n" ); document.write( "\n" ); document.write( " $\"area_of_ABDE=area_of_CEA+-area_of_CDB\"$ \r
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\n" ); document.write( "\n" ); document.write( "the $\"area_of_CEA=%28%288cm%2BDEcm%29%2A9cm%29%2F2\"$ ->as you can see, we need to find $\"DE\"$ \r
\n" ); document.write( "\n" ); document.write( "since $\"CEA\"$ and $\"CDB\"$ are $\"similar\"$ triangles, $\"corresponding\"$ sides are $\"proportional\"$ ; so, we have\r
\n" ); document.write( "\n" ); document.write( " $\"8%3A6=%288%2BDE%29%3A9\"$ ...solve for $\"+ED\"$
\n" ); document.write( " $\"8%2A9=%288%2BDE%29%2A6\"$
\n" ); document.write( " $\"72=48%2B6DE\"$
\n" ); document.write( " $\"72-48=6DE\"$
\n" ); document.write( " $\"24=6DE\"$
\n" ); document.write( " $\"DE=24%2F6\"$
\n" ); document.write( " $\"DE=4cm\"$ \r
\n" ); document.write( "\n" ); document.write( "and the $\"area_+of_+CEA=%28%288cm%2B4cm%29%2A9cm%29%2F2+=%2812cm%2A9cm%29%2F2=6cm%2A9cm=54cm%5E2\"$ \r
\n" ); document.write( "\n" ); document.write( " the $\"area_of_CDB=%288cm%2A6cm%29%2F2=4cm%2A6cm=24cm%5E2\"$ \r
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\n" ); document.write( "\n" ); document.write( "finally,the area o the trapezium
\n" ); document.write( " $\"area_of_ABDE=54cm%5E2-24cm%5E2=30cm%5E2\"$ \r
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