document.write( "Question 1125317: Two airplanes left the same airport and arrived at the same destination at the same time. The first airplane left at 8:00 a.m. and traveled at an average rate of 496 miles per hour. The second airplane left at 8:30 a.m. and traveled at an average rate of 558 miles per hour. Let x represent the number of hours that the first plane traveled.\r
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document.write( "How many hours did it take the first plane to travel to the destination? \n" );
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Algebra.Com's Answer #741683 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "Here is an alternative to the usual algebraic solution method used by the other tutor. \n" ); document.write( "For many (probably most) students the algebraic method is easier to use. But try this one and see if it works for you. \n" ); document.write( "The ratio of the speeds of the two planes is 496:558 = 8:9. Since the distances are the same, the ratio of times is 9:8. \n" ); document.write( "So we can let 9x be the amount of time the first plane took and 8x be the amount of time the second plane took. \n" ); document.write( "Then since the difference in flight times was half an hour, 9x-8x=x = .5 hours. \n" ); document.write( "Then the flight time for the first plane was 9x=4.5 hours and the time for the second plane was 8x=4 hours. \n" ); document.write( " |