document.write( "Question 1125359: A jet flying at an altitude of 35,000 ft passes over a small plane flying at 10,000 ft headed in the same direction. The jet is flying twice as fast as the small plane , and 30 mins later they are 100 mi apart. Find the speed of each plane.\r
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Algebra.Com's Answer #741677 by ankor@dixie-net.com(22740)\"\" \"About 
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A jet flying at an altitude of 35,000 ft passes over a small plane flying at 10,000 ft headed in the same direction.
\n" ); document.write( " The jet is flying twice as fast as the small plane, and 30 mins later they are 100 mi apart.
\n" ); document.write( " Find the speed of each plane.
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\n" ); document.write( "Their difference in flight paths are 25,000 ft which is 4.7 mi apart but that is not enough to make a difference in the way we solve this problem.
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\n" ); document.write( "let s = the speed of the slower plane
\n" ); document.write( "then
\n" ); document.write( "2s = the speed of the jet
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\n" ); document.write( "Write a distance equation, dist = time * speed
\n" ); document.write( "\"1%2F2\"*(2s-s) = 100
\n" ); document.write( "2s - s = 200
\n" ); document.write( "s = 200 mph is speed of the slower plane
\n" ); document.write( "then obviously
\n" ); document.write( "400 mph is the speed of the jet
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