document.write( "Question 1125346: The length of a rectangle is 15 cm more than its width (w). A blue rectangle, which is 5 cm wider and 2 cm shorter than the red one, has a perimeter 72 cm. Make a sketch of the rectangles expressing all dimensions in terms of (w). Then find the dimensions of each rectangle.
\n" ); document.write( "I got this straight out of my textbook and I attempted to solve it, I got the red rectangle right but I didn't for the blue one.
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Algebra.Com's Answer #741668 by josgarithmetic(39618)\"\" \"About 
You can put this solution on YOUR website!
The drawing you could (and must) do yourself.\r
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\n" ); document.write( "The length of a RED rectangle is 15 cm more than its width (w). A blue rectangle, which is 5 cm wider and 2 cm shorter than the red one, has a perimeter 72 cm. Make a sketch of the rectangles expressing all dimensions in terms of (w). Then find the dimensions of each rectangle.
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\n" ); document.write( "\n" ); document.write( "Red Rectangle\r
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\n" ); document.write( "\n" ); document.write( "Length w+15
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\n" ); document.write( "\n" ); document.write( "Blue Rectangle\r
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\n" ); document.write( "\n" ); document.write( "Length, w+15-2=w+13
\n" ); document.write( "Width, w+5
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\n" ); document.write( "\n" ); document.write( "\"highlight_green%282%28w%2B13%29%2B2%28w%2B5%29=72%29\"
\n" ); document.write( "Simplify and solve this equation for w. Once done, you can evaluate the dimensions for the Red rectangle and for the Blue rectangle.\r
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\n" ); document.write( "\n" ); document.write( "(drawing the figures will help you see the situation more clearly.)
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