document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1125285>Question 1125285</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I am trying to understand proofs in geometry the question is ;<BR>\n" );
document.write( "Given S is the midpoint of line RU and line QT Prove line QR // line TU\r<BR>\n" );
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document.write( "How do I do this?<BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #741662 by </B><A HREF=/tutors/aboutme.mpl?userid=solver91311><B>solver91311(24713)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=solver91311><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=solver91311><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=741662\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> <font face=\"Times New Roman\" size=\"+2\">\r<BR>\n" );
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document.write( "QS = ST and RS = SU, both by defn of midpoint, hence segments QS and ST are congruent and RS and SU are congruent.  Angle QSR congruent Angle UST because they are vertical angles.  Hence, triangle QSR is congruent to triangle UST.  Then angle TUS is congruent to angle QRS by CPCT.  Then segment QR parallel to segment TU by equal opposite interior angles of a transversal.  You can't actually prove anything about line QR or line TU because QR and TU are line segments, NOT lines.  You can claim that the line CONTAINING segment QR is parallel to the line CONTAINING the segment TU.<BR>\n" );
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document.write( "John<BR>\n" );
document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\LARGE e^{i\pi}\ +\ 1\ =\ 0\"><BR>\n" );
document.write( "My calculator said it, I believe it, that settles it<BR>\n" );
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document.write( "<IMG STYLE=\"max-width:80%;\" SRC=\"/cgi-bin/rendertex.cgi?\Large \ \\r\"> </SPAN>\n" );
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