document.write( "Question 101984: solve the following formula for x2: d=(square root of: (x2-x1)^2 + (y2-y1) ^2). \n" ); document.write( "
Algebra.Com's Answer #74165 by Fombitz(32388)\"\" \"About 
You can put this solution on YOUR website!
\"D=sqrt%28%28x%5B2%5D-x%5B1%5D%29%5E2+%2B+%28y%5B2%5D-y%5B1%5D%29+%5E2%29%29\"
\n" ); document.write( "\"D%5E2=%28x%5B2%5D-x%5B1%5D%29%5E2+%2B+%28y%5B2%5D-y%5B1%5D%29+%5E2%29\" Square both sides to remove square root.
\n" ); document.write( " Use the additive inverse of \"%28y%5B2%5D-y%5B1%5D%29%5E2\".
\n" ); document.write( "\"D%5E2-%28y%5B2%5D-y%5B1%5D%29+%5E2=%28x%5B2%5D-x%5B1%5D%29%5E2\" Simplify.
\n" ); document.write( "+/-\"sqrt%28D%5E2-%28y%5B2%5D-y%5B1%5D%29+%5E2%29=%28x%5B2%5D-x%5B1%5D%29\" Take the square root of both sides, could be + or -.
\n" ); document.write( "\"x%5B1%5D\"+/-\"sqrt%28D%5E2-%28y%5B2%5D-y%5B1%5D%29+%5E2%29=+x%5B2%5D\" Use the additive inverse of \"x%5B1%5D\"}
\n" ); document.write( "\"x%5B2%5D=x%5B1%5D\"+/-\"sqrt%28D%5E2-%28y%5B2%5D-y%5B1%5D%29%5E2%29\" Final answer.
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