document.write( "Question 101952: use substitution to solve\r
\n" ); document.write( "\n" ); document.write( "x=2y+2
\n" ); document.write( "2x+3y=11
\n" ); document.write( "

Algebra.Com's Answer #74158 by mathemanic(13)\"\" \"About 
You can put this solution on YOUR website!
\"+x+=+2y+%2B+2+\" and \"+2x+%2B+3y+=+11+\"\r
\n" ); document.write( "\n" ); document.write( "By substituting the x of the second equation by the value in second equation, we'd have
\n" ); document.write( "\"+2%2A%282y+%2B+2%29+%2B+3y+=+11+\"
\n" ); document.write( "\"+4y+%2B+4+%2B+3y+=+11+\"
\n" ); document.write( "\"+4y+%2B+3y+=+11+-+4+\"
\n" ); document.write( "\"+7y+=+7+\"
\n" ); document.write( "\"+y+=+1+\"\r
\n" ); document.write( "\n" ); document.write( "To find the value of x, substitute the value of y = 1 to the first equation
\n" ); document.write( "\"+x+=+2%2A1+%2B+2+\"
\n" ); document.write( "\"+x+=+2+%2B+2+\"
\n" ); document.write( "\"+x+=+4+\"\r
\n" ); document.write( "\n" ); document.write( "Cheers :)
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