document.write( "Question 1125267: УSue is starting a lawn-cutting business. Her start-up cost to buy two lawn mowers and an edge trimmer is $665. She has figured out that she will use about $1 in gas for each lawn. If she charges $20 per lawn, what will her break-even point be? У
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Algebra.Com's Answer #741563 by josmiceli(19441) $\"\"$ $\"About$

You can put this solution on YOUR website!
Let $\"+n+\"$ = number of lawns mowed
\n" ); document.write( "Income equation:
\n" ); document.write( " $\"+I+=+20n+\"$
\n" ); document.write( "Expenses equation:
\n" ); document.write( " $\"+E+=+1%2An+%2B+665+\"$
\n" ); document.write( "Profit equation:
\n" ); document.write( " $\"+P+=+I+-+E+\"$
\n" ); document.write( "Break even point is where $\"+P+=+0+\"$
\n" ); document.write( " $\"+20n+-+%28+n+%2B+665+%29+=+0+\"$
\n" ); document.write( " $\"+19n+=+665+\"$
\n" ); document.write( " $\"+n+=+35+\"$
\n" ); document.write( "Break even is at 35 lawns mowed
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\n" ); document.write( "Check:
\n" ); document.write( " $\"+I+=+20%2A35+\"$
\n" ); document.write( " $\"+I+=+700+\"$
\n" ); document.write( "And
\n" ); document.write( " $\"+E+=+35+%2B+665+\"$
\n" ); document.write( " $\"+E+=+700+\"$
\n" ); document.write( "And
\n" ); document.write( " $\"+P=+0+\"$ \r
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