document.write( "Question 1125183: A chemical company makes two brands of antifreeze. The first brand is 40% pure antifreeze, and the second brand is 95% pure antifreeze. In order to obtain 110 gallons of a mixture that contains 60% pure antifreeze, how many gallons of each brand of antifreeze must be used? \n" ); document.write( "

Algebra.Com's Answer #741496 by josgarithmetic(39617) $\"\"$ $\"About$

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$\"40%28110-x%29%2B95x=60%2A110\"$ , if x is how many gallons of the 95% pure antifreeze to use\r
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\n" ); document.write( "\n" ); document.write( " $\"40%2A110-40x%2B95x=60%2A110\"$
\n" ); document.write( " $\"55x=60%2A110-40%2A110\"$
\n" ); document.write( " $\"55x=20%2A110\"$
\n" ); document.write( " $\"highlight%28x=40%29\"$ \r
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\n" ); document.write( "\n" ); document.write( "70 gallons of the 40%
\n" ); document.write( "40 gallons of the 95% \n" ); document.write( "

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