document.write( "Question 1125128: Evaluate h(2), where h=gºf.
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Algebra.Com's Answer #741451 by ikleyn(52793)\"\" \"About 
You can put this solution on YOUR website!
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document.write( "First evaluate f(2),   where f(x) = \"%281%2F2%29%2Ax%2B1\" :\r\n" );
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document.write( "    f(2) = \"%281%2F2%29%2A2%2B1\" = 1 + 1 = 2.\r\n" );
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document.write( "And then evaluate g(f(2)) = g(2) = \"sqrt%282%29\".\r\n" );
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document.write( "It is your ANSWER.\r\n" );
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\n" ); document.write( "\n" ); document.write( "The second way.\r
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document.write( "Start developing the general formula for  gof(x) :\r\n" );
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document.write( "    gof(x) = g(f(x)) = \"sqrt%28%281%2F2%29x%2B1%29\" = \"sqrt%28%28x%2B2%29%2F2%29\"\r\n" );
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document.write( "and then substitute x= 2 into this formula\r\n" );
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document.write( "    gof(2) = \"sqrt%28%282%2B2%29%2F2%29\" = \"sqrt%284%2F2%29\" = \"sqrt%282%29\".\r\n" );
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\n" ); document.write( "\n" ); document.write( "By doing any way,  you get the same  ANSWER :   gof(2) = \"sqrt%282%29\".\r
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