document.write( "Question 1125025: Every day, Quinn either gains two pounds (with probability 1/2) or loses one pound (with probability 1/2). Each day these probabilities are independent of whether she lost or gained weight any other day. \r
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document.write( "At the end of four days, what's the probability that Quinn will weigh one pound less than she did before?
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document.write( "At the end of four days, what's the probability that Quinn will weigh one pound more than she did before?
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document.write( "Enter your answers as whole numbers or fractions in lowest terms. \n" );
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Algebra.Com's Answer #741360 by greenestamps(13200)![]() ![]() You can put this solution on YOUR website! \n" ); document.write( "There are five possible changes in her weight over the four days: \n" ); document.write( "(1) gain all four days: 4(+2) = +8 \n" ); document.write( "(2) gain 3 of 4 days: 3(+2)+1(-1) = +5 \n" ); document.write( "(3) gain 2 of 4 days: 2(+2)+2(-1) = +2 \n" ); document.write( "(4) gain 1 of 4 days: 1(+2)+3(-1) = -1 \n" ); document.write( "(5) gain 0 of 4 days: 4(-1) = -4 \n" ); document.write( "From this, we can see that the answer to the second question is 0 -- there is no possibility that her change in weight over four days is equal to +1. \n" ); document.write( "We also see that to lose one pound over the 4 days, she needs to gain 1 day and lose 3 days. There are 4 ways she can do that -- do the weight gain on any one of the 4 days. \n" ); document.write( "There are 2 ways her weight can go each day; so over 4 days the number of different sequences of weight gains or losses is 2*2*2*2 = 2^4 = 16. \n" ); document.write( "So the probability of losing 1 pound over the 4 days is 4/16 = 1/4. \n" ); document.write( " |