document.write( "Question 1124787: What is the area of an isosceles trapezoid, if the lengths of its bases are 16 cm and 30 cm and the diagonals are perpendicular to each other? \n" ); document.write( "
Algebra.Com's Answer #741355 by ikleyn(52781)\"\" \"About 
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document.write( "Let A, B, C and D are the vertices of the trapezoid, so the trapezoid is ABCD.\r\n" );
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document.write( "Let AB be the longer base of 30 cm and CD be the other base of 16 cm long.\r\n" );
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document.write( "Let the point O be the intersection of diagonals.\r\n" );
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document.write( "Then the triangles  AOB,  BOC,  COD  and  AOD  are right angled triangles.\r\n" );
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document.write( "Since the trapezoid ABCD has equal lateral sides, the triangle AOB is isosceles right angled triangle.\r\n" );
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document.write( "Since it base AB is 30 cm long,  its sides (the legs)  AO and  BO  are  \"30%2Fsqrt%282%29\" cm long.\r\n" );
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document.write( "Similarly, the triangle COD is isosceles right angled triangle.\r\n" );
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document.write( "Since it base CD is 16 cm long,  its sides (the legs) CO and  DO  are  \"16%2Fsqrt%282%29\" cm long.\r\n" );
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document.write( "Now the areas of the triangles are\r\n" );
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document.write( "    for triangle  AOB:   \"0.5%2A%2830%2Fsqrt%282%29%29%2A%2830%2Fsqrt%282%29%29\" = 225 cm^2;\r\n" );
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document.write( "    for triangle  COD:   \"0.5%2A%2816%2Fsqrt%282%29%29%2A%2816%2Fsqrt%282%29%29\" =  64 cm^2;\r\n" );
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document.write( "    for triangle  BOC:   \"0.5%2A%2830%2Fsqrt%282%29%29%2A%2816%2Fsqrt%282%29%29\" = 120 cm^2;\r\n" );
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document.write( "    for triangle  AOD:   \"0.5%2A%2830%2Fsqrt%282%29%29%2A%2816%2Fsqrt%282%29%29\" = 120 cm^2.\r\n" );
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document.write( "The total area of the trapezoid is the sum of areas of triangles  225 + 64 + 120 + 120 = 529 cm^2.\r\n" );
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