document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=101812>Question 101812</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The distance traveled by a ball rolling down a ramp is given by s(t)=3.5t^2, where t is the time in seconds after the ball is released, and s(t) is measured in feet.  find the average velocity of the ball on the interval from t=1.0 seconds to t=1.5 seconds.  thanks so much!!!  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #74134 by </B><A HREF=/tutors/aboutme.mpl?userid=scott8148><B>scott8148(6628)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=scott8148><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=scott8148><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=74134\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the average velocity is the change in distance divided by the change in time\r<BR>\n" );
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document.write( "the distance change is s(1.5)-s(1) ... the time change is 1.5-1\r<BR>\n" );
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document.write( "(3.5(1.5^2)-3.5(1^2))/(1.5-1) ... (3.5(1.25))/.5 ... v=8.75 ft/sec </SPAN>\n" );
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