document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1124989>Question 1124989</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the measures of the three angles of a triangle is equal to 180 degrees. In a given triangle, the second angle measures 20 degrees more than the first and the third, 35 degrees more than the second. What is the measure of each of these angles </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #741315 by </B><A HREF=/tutors/aboutme.mpl?userid=Theo><B>Theo(13342)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Theo><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Theo><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=741315\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> let the angles be A,B,C.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "the sum of the angles is 180 degrees, therefore A + B + C = 180.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "the second angle measures 20 degrees more than the first, therefore B = A + 20.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "the third angle measures 35 degrees more than the second, therefore C = B + 35.<BR>\n" );
document.write( "since B = A + 20, then replace B in C = B + 35 to get C = A + 20 + 35.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "you now have:\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "B = A + 20<BR>\n" );
document.write( "C = A + 55\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "the sum of (A,B,C) = 180<BR>\n" );
document.write( "in this equation, replace B with A + 20 and C with A + 55 to get:<BR>\n" );
document.write( "A + A + 20 + A + 55 = 180<BR>\n" );
document.write( "combine like terms to get:<BR>\n" );
document.write( "3A + 75 = 180<BR>\n" );
document.write( "subtract 75 from both sides of this equation to get:<BR>\n" );
document.write( "3A = 105<BR>\n" );
document.write( "solve for A to get:<BR>\n" );
document.write( "A = 105 / 3 = 35\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "you get:<BR>\n" );
document.write( "A = 35<BR>\n" );
document.write( "B = A + 20 = 55<BR>\n" );
document.write( "C = A + 55 = 90\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "A + B + C = 35 + 55 + 90 = 180.<BR>\n" );
document.write( "B = A + 20 = 35 + 20 = 55<BR>\n" );
document.write( "C = B + 35 = 55 + 35 = 90\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "everything chcks out so the solution looks good.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( "the solution is that the measure of each angle is {35, 55, 90}.\r<BR>\n" );
document.write( "<BR>\n" );
document.write( "\n" );
document.write( " </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );