document.write( "Question 14916: Twice the greater of two consecutive odd intgers is 13 less than three times the lesser. Find the integers. \n" ); document.write( "

Algebra.Com's Answer #7413 by elima(1433) $\"\"$ $\"About$

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First of all two consecutive integers would be:
\n" ); document.write( "x, x+2;
\n" ); document.write( "Now we have twicw the greater; which the greater would be;
\n" ); document.write( "x+2; so twice that = 2(x+2);
\n" ); document.write( "And the word is in a word problem means =;
\n" ); document.write( "So far we have;
\n" ); document.write( "2(x+2)=
\n" ); document.write( "Now 13 less than(-) 3 times(*) the lesser, the lesser integer would be x;
\n" ); document.write( "so we have 3x-13
\n" ); document.write( "Now we put those together and we have;
\n" ); document.write( "2(x+2)=3x-13;
\n" ); document.write( "Now lets solve;
\n" ); document.write( "2x+4=3x-13, add 13 to both sides;
\n" ); document.write( "2x+4+13=3x-13+13
\n" ); document.write( "2x+17=3x; now subtract 2x from both sides;
\n" ); document.write( "2x+17-2x=3x-2x
\n" ); document.write( "17=x
\n" ); document.write( "So x being the lesser of the two odd integers = 17;
\n" ); document.write( "x+2=17+2=19
\n" ); document.write( "So the odd integers are 17,19
\n" ); document.write( "Hope you understand
\n" ); document.write( "=) \n" ); document.write( "

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