document.write( "Question 101938: The perimeter of a rectangle is 74 ft. The length is 7 ft more than twice the width. What are the dimensions of the rectangle? \n" ); document.write( "
Algebra.Com's Answer #74129 by brianuh(2)![]() ![]() ![]() You can put this solution on YOUR website! p = l X w\r \n" ); document.write( "\n" ); document.write( "l = 2w +7\r \n" ); document.write( "\n" ); document.write( "74 = w X 2w + 7\r \n" ); document.write( "\n" ); document.write( "67 = 3w\r \n" ); document.write( "\n" ); document.write( "67/3 = 22.3\r \n" ); document.write( "\n" ); document.write( "22.3 = w\r \n" ); document.write( "\n" ); document.write( "l = 22.3 X 2 + 7\r \n" ); document.write( "\n" ); document.write( "l = 89.3 \n" ); document.write( "w = 22.3\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |