document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1124867>Question 1124867</A>: <I><SPAN STYLE=\"word-break: break-all;\"> At what simple interest rate will a sum triple itself in 15 years? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #741162 by </B><A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><B>amarjeeth123(569)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=amarjeeth123><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=741162\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let the principal be x.<BR>\n" );
document.write( "Then the amount is 3x.<BR>\n" );
document.write( "Let the rate be r.<BR>\n" );
document.write( "Time=t=15 years<BR>\n" );
document.write( "In simple interest amount=P*t*r/100<BR>\n" );
document.write( "Plugging in the values we get,<BR>\n" );
document.write( "3x=x*15*r/100<BR>\n" );
document.write( "Multiplying both sides of the equation by 100 we get,<BR>\n" );
document.write( "3x*100=15rx<BR>\n" );
document.write( "300x=15rx<BR>\n" );
document.write( "15r=300<BR>\n" );
document.write( "r=20<BR>\n" );
document.write( "The rate of interest is 20%. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );