document.write( "Question 1124794: Suppose that 50 identical batteries are being tested. After 8 hours of continuous use, assume that a given battery is still operating with a probability of 0.70 and has failed with a probability of 0.30. \r
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document.write( "What is the probability that fewer than 25 batteries will last at least 8 hours? \n" );
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Algebra.Com's Answer #741103 by Boreal(15235) You can put this solution on YOUR website! The mean would be 35 batteries (50*0.7) \n" ); document.write( "The variance would be 10.5 (mean*0.3) \n" ); document.write( "The sd would be sqrt (10.5) or 3.24 \n" ); document.write( "the continuity correction factor would be z<(24.5-35)/3.24 of z< 10.5/3.24 =3.24 \n" ); document.write( "probability is 0.0006\r \n" ); document.write( "\n" ); document.write( "Check 50C24*0.7^24*0.3^26=0.000592 \n" ); document.write( "50C23*0.7^24*0.3^27=0.00016 \n" ); document.write( "the others will be far smaller. \n" ); document.write( " |