document.write( "Question 1124800: You need a 65% alcohol solution. On hand, you have a 385 mL of a 60% alcohol mixture. How much pure alcohol will you need to add to obtain the desired solution?
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Algebra.Com's Answer #741087 by josmiceli(19441)\"\" \"About 
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Let \"+x+\" = ml of pure alcohol needed
\n" ); document.write( "\"+.6%2A385+=+231+\" ml of alcohol in 60% mixture
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\n" ); document.write( "\"+%28+x+%2B+231+%29+%2F+%28+x+%2B+385+%29+=+.65+\"
\n" ); document.write( "\"+x+%2B+231+=+.65%2A%28+x+%2B+385+%29+\"
\n" ); document.write( "\"+x+%2B+231+=+.65x+%2B+250.25+\"
\n" ); document.write( "\"+.35x+=+19.25+\"
\n" ); document.write( "\"+x+=+55+\"
\n" ); document.write( "55 ml of pure alcohol are needed
\n" ); document.write( "Check:
\n" ); document.write( "\"+%28+55+%2B+231+%29+%2F+%28+55+%2B+385+%29+=+.65+\"
\n" ); document.write( "\"+286+%2F+440+=+.65+\"
\n" ); document.write( "\"+.65+=+.65+\"
\n" ); document.write( "OK
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