document.write( "Question 1124653: A piece of wire is shaped to enclose an equilateral triangle whose area is 27.71cm^2. It is then reshaped to enclose a rectangle whose length is 9cm., find the area of the rectangle \n" ); document.write( "
Algebra.Com's Answer #740983 by rothauserc(4718)![]() ![]() You can put this solution on YOUR website! let s be the length of a side of the equilateral triangle \n" ); document.write( ": \n" ); document.write( "area of equilateral triangle in terms of s is \n" ); document.write( ": \n" ); document.write( "Area = s^2 * square root(3)/4 \n" ); document.write( ": \n" ); document.write( "Note this formula comes from the fact that the base is s/2 and height = s * square root(3)/2 for an equilateral triangle \n" ); document.write( ": \n" ); document.write( "27.71 = s^2 * square root(3)/4 \n" ); document.write( ": \n" ); document.write( "s^2 = (4 * 27.27)/square root(3) = 62.9774 \n" ); document.write( ": \n" ); document.write( "s = square root(62.9774) is approximately 7.94 cm \n" ); document.write( ": \n" ); document.write( "Perimeter of the equilateral triangle is 3 * 7.94 = 23.82 cm \n" ); document.write( ": \n" ); document.write( "Perimeter of rectangle is 2l + 2w where l is length and w is width \n" ); document.write( ": \n" ); document.write( "we are given that l=9 \n" ); document.write( ": \n" ); document.write( "2(9) +2w = 23.82 \n" ); document.write( ": \n" ); document.write( "2w = 23.82 -18 = 5.82 \n" ); document.write( ": \n" ); document.write( "w = 2.91 cm \n" ); document.write( ": \n" ); document.write( "Area of rectangle(A) = l * w \n" ); document.write( ": \n" ); document.write( "************************* \n" ); document.write( "A = 9 * 2.91 = 26.19 cm^2 \n" ); document.write( "************************* \n" ); document.write( ": \n" ); document.write( " |