document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=101910>Question 101910</A>: <I><SPAN STYLE=\"word-break: break-all;\"> We have tried and tried to find the answer, but can't seem to figure out when to use the multipicative inverse to solve it.  The problem is:<BR>\n" );
document.write( "2^2x = 8^(x-1) Hope you can help.  Thanks! </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #74095 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=74095\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The problem is:<BR>\n" );
document.write( "2^2x = 8^(x-1) <BR>\n" );
document.write( "------------------<BR>\n" );
document.write( "Write both sides to the base 2 as follows:<BR>\n" );
document.write( "2^(2x) = (2^3)^(x-1)<BR>\n" );
document.write( "2^2x = 2^[3x-3]<BR>\n" );
document.write( "Since the bases are the same the exponents are equal.<BR>\n" );
document.write( "2x = 3x-3<BR>\n" );
document.write( "-x = -3<BR>\n" );
document.write( "x = 3<BR>\n" );
document.write( "===========<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );