document.write( "Question 1124614: snajay wants to earn extra money for college. Because he like baking, he decided to sell chocolate chip cookies on campus. The cost to start his business s $120 and each cookie costs 10 cents to make. He will sell the cookies for 50 cents each. How many cookies does he need to sell to break even?\r
\n" ); document.write( "\n" ); document.write( "I am a little confused with this question, since we are learning to develop two equations to find the point of intersection. Some help would be great please! I cant figure out what the two equations are supposed to be. \n" ); document.write( "
Algebra.Com's Answer #740928 by math_helper(2461)\"\" \"About 
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On the one hand there is a cost equation. This represents the money he needs to spend (in dollars) to make x cookies:
\n" ); document.write( "C(x) = 120 + (0.1)x
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\n" ); document.write( "\n" ); document.write( "Now when he sells cookies, there is a revenue equation for x cookies sold. This represents the money he takes in:
\n" ); document.write( "R(x) = (0.5)x
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\n" ); document.write( "\n" ); document.write( "He breaks even when R(x) = C(x):
\n" ); document.write( "(0.5)x = 120+(0.1)x
\n" ); document.write( "(0.4)x = 120
\n" ); document.write( " x = 120/(0.4) = 300
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\n" ); document.write( "\n" ); document.write( "You can also plot R(x) and C(x) to see where they intersect. \r
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