document.write( "Question 1124548: Please show me step by step about this question. I’m preparing for my 1st out 4 exams on my math class in a week today.
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document.write( "Here’s the question: for the following piecewise functions, graph, state, domain, range and intercepts
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document.write( "F(x)=3x+4 if-2<=x<0
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document.write( " -3 if x=0
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document.write( " -2x if x>0
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document.write( "Thanks! \n" );
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Algebra.Com's Answer #740880 by Boreal(15235)![]() ![]() You can put this solution on YOUR website! From -2 to 0 with 0 open, the graph is 3x+4, up and to the right, with domain -2 to 0 and range -2 at the left end to 4 open at the right end. There is an x-intercept at -4/3. \n" ); document.write( "at x=0, y=-3, which adds a point to the range and nothing to the domain. It is the y-intercept. \n" ); document.write( "at x>0, it is -2x, which makes the range from 0 to - oo for this part, and therefore makes the whole range from -oo to 4 open. The domain is x from -2 to +oo.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "At 0, the function is -3, and that is a solid point. There should be an open point for the two lines at x=0. \n" ); document.write( "The domain is [-2, oo) \n" ); document.write( "The range is (-oo, 4] \n" ); document.write( "The x-intercept is at (-4/3, 0). \n" ); document.write( "The y-intercept is at (0, -3). \n" ); document.write( "While there is a second \"crossing\" of the x-axis, it is a jump and not a point. \n" ); document.write( " |