document.write( "Question 1124567: Find the equation of tangent line at the point (2,1) on the circle 2x^2+2y^2=5x. \n" ); document.write( "
Algebra.Com's Answer #740876 by htmentor(1343)\"\" \"About 
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From implicit differentiation, we get:
\n" ); document.write( "4x + 4y(dy/dx) = 5
\n" ); document.write( "Thus the slope of the tangent line, dy/dx = (5 - 4x)/4y
\n" ); document.write( "Using the point slope form and x = 2, y = 1, we get:
\n" ); document.write( "y - 1 = ((5-8)/4)(x - 2)
\n" ); document.write( "Simplify:
\n" ); document.write( "y = (-3/4)x + 10/4
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