document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1124491>Question 1124491</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Use the model for the period of a pendulum, T, such that <BR>\n" );
document.write( "T = 2&#960; sqrt(L/g) where the length of the pendulum is L and the acceleration due to gravity is g. \r<BR>\n" );
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document.write( "If the gravity is 32 ft/s^2  and the period equals 9 s, find the length to the nearest in. <BR>\n" );
document.write( "(12 in. = 1 ft).<BR>\n" );
document.write( " Round your answer to the nearest in.  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #740802 by </B><A HREF=/tutors/aboutme.mpl?userid=rothauserc><B>rothauserc(4718)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=rothauserc><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=rothauserc><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=740802\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> 2 * pi * sqrt(L/g) = T<BR>\n" );
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document.write( "2 * (22/7) * sqrt(L/32) = 9<BR>\n" );
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document.write( "sqrt(L/32) = 9 * 7/44 = 1.4318<BR>\n" );
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document.write( "L/32 = 2.05<BR>\n" );
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document.write( "L = 65.6 feet<BR>\n" );
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document.write( "0.6 of 12 inches is 7.2 or approximately 7 inches<BR>\n" );
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document.write( "65 * 12 + 7 = 787 inches<BR>\n" );
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