document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1124472>Question 1124472</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Hi<BR>\n" );
document.write( "tap X can fill a tank in 10 min. Tank Y can empty it in 6 min. Both taps are turned on at the same time <BR>\n" );
document.write( "and the tank is 3/4 full. How long will it take to reach the stage when the tank is empty and the water flowing in from X is immediately emptied through Y.\r<BR>\n" );
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document.write( "thanks </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #740778 by </B><A HREF=/tutors/aboutme.mpl?userid=Alex.33><B>Alex.33(110)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alex.33><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alex.33><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=740778\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Let me suppose the tank's volume is V litres. Then<BR>\n" );
document.write( "speed of x: +V/10 litre/min <BR>\n" );
document.write( "speed of y: -V/6 litre/min<BR>\n" );
document.write( "/*The positive/negative sign shows the increase/decrease of water volume.*/<BR>\n" );
document.write( "Initially the water is 3V/4. Let's begin.<BR>\n" );
document.write( "3V/4+V*t/10-V*t/6=0<BR>\n" );
document.write( "t=45/4=11.25 minutes.\r<BR>\n" );
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document.write( "And we're done. Figure out what we want. Extract useful material from the question. Design the approach. Do.<BR>\n" );
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