document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=1124455>Question 1124455</A>: <I><SPAN STYLE=\"word-break: break-all;\"> A restaurant offers a choice of 6 appetizers, 15 entrees, and 5 desserts. How many meals consisting of one appetizer, two DIFFERENT entrees, and one dessert are possible?  <BR>\n" );
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document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #740776 by </B><A HREF=/tutors/aboutme.mpl?userid=Alex.33><B>Alex.33(110)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Alex.33><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Alex.33><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=740776\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> choose 1 appetizer: 6c1=6 ways.<BR>\n" );
document.write( "choose 2 DIFFERENT entrees: 15c2=105 ways.<BR>\n" );
document.write( "choose 1 dessert: 5c1=5 ways.<BR>\n" );
document.write( "multiply all: 3150 ways.\r<BR>\n" );
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document.write( "#Basic combination approach is the most applicable way when it comes to calculating number of possible outcomes. </SPAN>\n" );
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